0.125x^2-0.25x=10

Solution for 0.125x^2-0.25x=10 equation:

0.125x^2-0.25x=10

We move all terms to the left:

0.125x^2-0.25x-(10)=0

a = 0.125; b = -0.25; c = -10;
Δ = b2-4ac
Δ = -0.252-4·0.125·(-10)
Δ = 5.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{5.0625}}{2*0.125}=\frac{0.25-\sqrt{5.0625}}{0.25}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{5.0625}}{2*0.125}=\frac{0.25+\sqrt{5.0625}}{0.25}
$